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4x/(x²-9)-2/(x+3) = 4x/((x+3)(x-3))-2/(x+3) = 4x/((x+3)(x-3))-2(x-3)/((x+3)(x-3)) = (4x-2(x-3))/((x+3)(x-3)) = (2x+6)/((x+3)(x-3) = (2(x+3))/((x+3)(x-3)) = 2/(x-3)

For x = 2, y = 16. Calculate the gradient of the curve at y = 2, dy/dx = 6x^2, dy/dx = 24. This is also the gradient of the tangent to the curve at x = 2. It is a rule that the products of the gradients o...

This question challenges a students skills with integration and trigonometry a very common question on Core 4 papers that can leave students struggling. First we use our knowledge that cosecy=1/siny and m...

First we need to find the intersection point(s) of L and C so set 6x-x²=16-2x and rearrange to get x²-8x+16=0 so (x-4)²=0.Repeated root so line is tangent to the curve at ...

rewrite the equation in a more helpful way:y=8x² + 2x^-1 differentiate:dy/dx = 16x -2x^-2set equal to 0 and solve for x16x -2x^-2 = 016x -2/ x²=016x= 2/...