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a) I would start by trying to see if the student can do it by himself. In the case the student does not know how to start, I would start by asking him if can find the general term. Here there are two ways...
First, you equate the 2 equations to get this single quadratic equation (x^2-5x+9=0). And then evaluate the expression b^2-4ac. If b^2 -4ac is < 0 then they do not intersect. In our case b^2 -4ac is -9...
140/5 = 28140 - 28 = 1123 + 4 = 7112/7 = 1616 x 3 = 48Answer: 48 (Would go through methods with student: order of thinking, dealing with ratio, long division)
First rearrange the equation to get 2y = 7x + 11.Then divide through by 2 to get the equation for y: y=7x/2 +11/2Now differentiate with respect to x to find the gradient function: dy/dx=7/2 + 0We hav...
Once you have found the stationary point of the equation by differentiating the equation and equating it to zero. You can then find out if the point you have found is a maximum, minimum or point of inflec...
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