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Simultaneous equations have two or more unknown values, in this case there are two: x and y. To solve them, first we need to get one unknown by itself. In order to do this we need the coefficient of eithe...

y = x*ln(x)Let u = x, v = ln(x) => du/dx = 1, dv/dx = 1/x=> y = uv=> dy/dx = (du/dx)v + u(dv/dx) USING PRODUCT RULETherefore y = ln(x) + 1

There are three things to think about when sketching a quadratic graph: whether its a 'u' or 'n' shape, where it cuts across the y axis and where it cuts across the x axis (if it does). Let's look at an e...

The mean height of all the students is 1.48m which means that the total height of all the students is 30 * 1.48m = 44.4m. The contribution due to the boys is 14 * 1.52m = 21.28m. Therefore the total heigh...

2s = d/t. Multiply both sides of the equation by t to give 2ts = d. Then, divide both sides of the equation by 2s to give t = d/2s.