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If y = ln (x+1) sin x , find dy/dx

u = ln (x+1) v = sin x
du/dx = 1/(x+1) dv/dx = cos x
Therefore, by the product rule,
dy/dx = [sin x / x+1] + [ln (x+1) cos x]

EC
Answered by Edward C. Maths tutor
6361 Views

Find the gradient of the curve y=2sinx/x^3 at the point x=

  1. To find the gradient of the curve we must differentiate the function. The function is in the form of a quotient, y=u/v, where u and v are functions of x. Therefore, we can use the quotient rule, dy/...
HM
Answered by Holly M. Maths tutor
3762 Views

Differentiate y=x^4sinx

  1. Firstly, we must recognise that the function is in the form of a product, y=uv, where u and v are functions of x. Therefore, we can use the product rule, dy/dx = u (dv/dx) + v (du/dx). 2) We can wri...
HM
Answered by Holly M. Maths tutor
7251 Views

Given that y= 5x^2 + 2x , find dy/dx

5x^2 becomes 25x as the 2 comes down and 2x becomes 2 as x becomes 1.dy/dx = 25x + 2=10x+2

CD
Answered by Camille D. Maths tutor
4241 Views

How do I find the inverse of a function?

To find the inverse of a function you need to rearrange from y= a function in terms of x to x=a function in terms of y and then when you write your answer it's important to set it in the...

NH
Answered by Natalie H. Maths tutor
2989 Views

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