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Find the derivative of the equation y = x*ln(x)

y = x*ln(x)Let u = x, v = ln(x) => du/dx = 1, dv/dx = 1/x=> y = uv=> dy/dx = (du/dx)v + u(dv/dx) USING PRODUCT RULETherefore y = ln(x) + 1

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Answered by Owen B. Maths tutor
4071 Views

How do you sketch a quadratic graph?

There are three things to think about when sketching a quadratic graph: whether its a 'u' or 'n' shape, where it cuts across the y axis and where it cuts across the x axis (if it does). Let's look at an e...

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Answered by Sita P. Maths tutor
3069 Views

A class has 30 students. The mean height of the 14 boys is 1.52m. The mean height of all the students is 1.48m. Work out the mean height of the girls.

The mean height of all the students is 1.48m which means that the total height of all the students is 30 * 1.48m = 44.4m. The contribution due to the boys is 14 * 1.52m = 21.28m. Therefore the total heigh...

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Answered by William D. Maths tutor
9143 Views

Rearrange 2s = d/t to make t the subject.

2s = d/t. Multiply both sides of the equation by t to give 2ts = d. Then, divide both sides of the equation by 2s to give t = d/2s.

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Answered by Prasanth P. Maths tutor
2649 Views

Differentiate z = e^(3y^2+5) with respect to y. (Hint: use chain rule.)

We can find dz/dy using chain rule dz/dy=dz/du x du/dy (1) by defining u=3y^2+5 (since the exponent of e is a function of y we call this function u) and rewrite z=e^u. Then, we find dz/du=e^u (2) and du/d...

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Answered by Sophie H. Maths tutor
2780 Views

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