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When dealing with questions to do with expanding brackets, you must multiply every term in one bracket with all the others in the second bracket. So for this question, we can see we have 4 termsAAAnswered by Ameer A. • Maths tutor5623 Views
With simultaneous equations there is more than one unknown. First we’ll get one unknown on its own so we rearrange the bottom equation to get x on its own. By adding y to each side of the equation this le...
To begin this question you need to bring all of the terms to one side, so the equation equals 0. It is easiest to do this by subtracting 1 from each side.x^2-3x-3-1=1-1x^2-3x-4=0Now we need to factorise t...
Our DE (Differential Equation) dx/dt = 8sin(2t)/(3sqrt(x)) is separable because dx/dt can be expressed as a product of two functions of the form dx/dt = f(t)g(x) = (8sin(2t)) * (1/(3sqrt(x))).To solve the...
Firstly, it's important to note that the question concerns straight lines, so it will be possible to express the answer in the form y=mx+c where m is the gradient and c is the y...
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