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The probability of picking a ball from a bag is the number of balls of that colour divided by the total number of balls.
Therefore in the first instance, the probability of a red ball is 3/9 or 1/3...
For the first ball the probability we pick a red ball is the same, it's the number of red balls divided by the total number of balls. Which in this case is 3/9.
If we replace the balls the chance ...
d/dx (xy) = x dy/dx + y
d/dx (y^2) = 2y dy/dx [This is from the chain rule]
So, d/dx (2x^2 + xy + y^2 = 14)
=> 4x + x dy/dx + y + 2y dy/dx = 0
set dy/dx = 0 as stationary ...
e.g. The dog lay on the mat.
The diagram would have the following:
An arrow pointing upwards labeled v(y)
An arrow pointing to the right labeled v(x)
An arrow pointing in between those lines with a degree between...
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