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Find the location of the turning point of the following curve, y = x^2 + 6x - 7

Turning point is when dy/dx = 0

if y= x2 + 6x - 7

dy/dx = 2x + 6

at turning point: 2x + 6 = 0

therefore: 2x = - 6

x coordinate: x = - 3

substitute into...

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Answered by Hugo M. Maths tutor
6509 Views

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