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Find dy/dx

Remember quotient rule dy/dx=(u'v-v'u)/v^2

u=4x       u'=4

v=x^2+5         v'=2x

dy/dx=(20-4x^2)/(x^2+5)^2 (simplified)

∫ 5e^3-4x dx=5∫e³ e^-4x dx=5e³ ∫e^-4x d=5e³ [(-1/4)e^-4x ]=-(5/4)e³e^-4x =-(5/4)e^3-4x...

First find the nth term of the sequence. Start by finding the difference between each term:

3, 5, 7, 9, 11 - the difference between each is 2 therefore it is 2n but this alone gives the sequence: 2...

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