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(x+6) and (x+5) are the length and width, respectively, of a rectangle with area 20. Calculate the width of the rectangle.

(x+6)(x+5)=20. x2 + 11x +30=20. x2+ 11x + 10 = 0. (x+10)(x+1)=0 . x=-1 and x=-10. width= -10+5=-5 (invalid solution). width =-1+5= 4. Checking through: (-1+6)*(-1+5)=20.

Answered by Maths tutor
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Three points have coordinates A(-8, 6), B(4, 2) and C(-1, 7). The line through C perpendicular to AB intersects AB at the point P. Find the equations of the line AB and CP.

To find the equation of a line, we need; the gradient of that line and a point on that line. To find the gradient of a line, we require two points on the line which have been prov...

RD
Answered by Ryan D. Maths tutor
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Given the circumference x^2 - 2x + y^2 = 3, find the position of the center P and the value of the Radius. Then find the intercepts with the y axis and the tangent to the circumference at the positive y intercept.

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