x^2 - 10x + 21 = 0

  • First, factorise the quadratic equation.
  • Find two numbers that multiply to give 21 and add to give 10. 7 and 3
  • (x-7)(x-3)=0
  • Now find the value x so that when these brackets are multiplied together the answer is 0.
  • So either x=7 or x=3
  • You can check the answer by substituting 7 and 3 into the equation.
Answered by Ben S. Maths tutor

3415 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 15x+10y=20 4x+5y=17


Solve algabraically: 6a+b=16 and 5a-2b=19


How do you complete the square?


Solve this set of simultaneous equations. 1. 4x+2y=12 2. 2x+3y=10


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy