The point A lies on the curve y=5(x^2)+9x , The tangent to the curve at A is parralel to the line 2y-x=3. Find an equation to this tangent at A.
y-(any value of the function)=0.5(x-(any value in the domain))
e.g. Point with point A being (1,14) The answer would be y-14=0.5(x-1)
RA
