expand and simplify (x+3)(x-7)

(x+3)(x-7)

= (xx) + (x-7) + (x3) + (3-7)

= x^2 - 7x + 3x - 21

= x^2 - 4x - 21

Key here is to ensure you multiply each term in one bracket by both in the other, and to keep careful track of the signs.

LP
Answered by Luke P. Maths tutor

25810 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Samuel had 3 piles of coins, I, II and III. Altogether there was 72p. Pile II had twice as much as pile I. Pile III had three times as much as pile II. How much money was in Pile III?


Prove that the square of an odd number is always one more than a multiple of 4


Solve the quadratic equation x^2-6x+5=0


Expand (1+2x)(4x+3)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning