Show that Sec2A - Tan2A = (CosA-SinA)/(CosA+SinA)

Sec2A - Tan2A Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double Angle Formula = (1 - 2SinACosA) / (Cos2A - Sin2A) Make use of 1 = Cos2x + Sin2x and Difference of two squares = (Cos2A + Sin2A - 2SinACosA) / (CosA + SinA)(CosA - SinA) Factorise the numerator = (CosA - SinA)2 / (CosA + SinA)(CosA - SinA) Divide out by (CosA - SinA) = (CosA - SinA) / (CosA + SinA)

JC
Answered by James C. Maths tutor

37706 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

y=e^(2x) - x^3. Find dy/dx. (please note this is "e to the power of 2x, minus x cubed")


Calculate the derivative of the following function: f(x)=cos(3x))^2


Solve the simultaneous equation y+4x+1=0 and y^2+5x^2+2x+0.


Express the fraction (p+q)/(p-q) in the form m+n√2, where p=3-2√2 and q=2-√2.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning