Find the value of x when 2x^2 - x - 6 = 0

2x2 - x - 6 = 0

This must first be factorised - I use the 'box method' when the reciprocal of x2 is >1. This is difficult to explain via writing but it involves a little trial and error.

2x + 3 --> (+3x)

x - 2 --> (-4x)

Therefore 2x2 - x - 6 = 0 can be factorised to give (2x+3)(x-2) = 0 - At this stage, you should multiply it out to check that you get the original equation. 

if 2x+3 = 0 --> 2x= -3 giving x = -3/2

if x-2 = 0  --> x = 2

Final check can be done by substituting each value of x into the original equation and ensuring the answer is 0.

GS
Answered by Gayathri S. Maths tutor

8418 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations x^2 + y^2 = 9 and y = 3x + 3


Solve the equation to 2 two decimal places: (2x+3/x-4 ) - (2x-8/2x+1) = 1


Solve algebraically the simultaneous equations 2x^2-y^2=17 and x+2y=1


what is the point of intersection between the lines 3y-4x=12 and 2x=2y+3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning