y = (x^2)sin(3x). Find dy/dx

We need to differentiate x2sin(3x). We know how to differentiate (x2) on its own, and how to differentiate sin(3x) on its own. So we can use the Product rule:

dy/dx = (d/dx(x2))sin(3x) + x2(d/dx(sin(3x))

          = (2x)sin(3x) + x2(3cos(3x))

          = 2xsin(3x) + 3x2cos(3x)

RD
Answered by Robert D. Maths tutor

19281 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Calculate dy/dx of the following equation: y = 3x^3 - 6x^2 + 2x - 6


How would you differentiate 3x^4 - 2x^2 + 9x - 1


How do I integrate terms with sin^2(x) and cos^2(x) in them? For example integrate (1+sin(x))^2 with respect to x


Given that y = 4x^5 - 5/(x^2) , x=/=0 , find a)dy/dx b)indefinite integral of y


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning