Find the equation of the straight line joining points (-1, -4) and (2, 5)

  1. Draw sketch of line 2. Find gradient using m=(y- y1)/(x- x1)= 5--4/2--1=9-3=3 3. Choose one of the points and call it (a,b). I'll pick (2,5) because there's no negaitves. 4. Sub into equation y-b=m(x-a)   y-5= 3(x-2) 5. Simplify  y - 5 = 3x - 6    y = 3x - 1
BM
Answered by Ben M. Maths tutor

8553 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If a right angled-triangle has sides A,B,C where A = 4 and B = 3 what is the value of side C?


What is completing the square?


Jo has the following 9 coins in her purse: 10p, 2p, 2p, 50p, 10p, 1p, 20p, 2p, 2p. Work out the median, mean, mode and range.


Solve the equations y = x + 1 and y = x^2 - 3x + 4 simultaneously.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning