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Find dy/dx of the curve x^3+5xy-2y^2-57=0

3x2+5y+5x(dy/dx)-4y(dy/dx)=0

3x2+5y=(5x-4y)dy/dx

dy/dx=(3x2+5y)/(5x-4y)

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Answered by Steven P. • Maths tutor

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