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Find dy/dx of the curve x^3+5xy-2y^2-57=0

3x²+5y+5x(dy/dx)-4y(dy/dx)=0

3x²+5y=(5x-4y)dy/dx

dy/dx=(3x²+5y)/(5x-4y)

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Answered by Steven P. • Maths tutor

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Find the general solution of 2 dy/dx - 5y = 10x

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