ln(2x^2 +9x-5) =1+ ln( x^2+2x-15)

Moving Ln to one side ln(2x^2 +9x-5) -  ln( x^2+2x-15) =1 Subtracting Ln is the same as dividing ln(((2x^2 +9x-5)/( x^2+2x-15)) ln((2x-1)/(x-3))=1 Taking e to both sides (2x-1)/(x-3)=e x=(1-3e)/(2-e)

RH
Answered by Raj H. Maths tutor

8983 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise fully 6xyz + 24x^2yz + 18xy^3z^2


Solve 7x - 3 = 4x + 6


Solve the following two equations simultaneously: 3x + y = 10, x + y = 4


Factorise the equation x^2 +5x = 6


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning