ln(2x^2 +9x-5) =1+ ln( x^2+2x-15)

Moving Ln to one side ln(2x^2 +9x-5) -  ln( x^2+2x-15) =1 Subtracting Ln is the same as dividing ln(((2x^2 +9x-5)/( x^2+2x-15)) ln((2x-1)/(x-3))=1 Taking e to both sides (2x-1)/(x-3)=e x=(1-3e)/(2-e)

Answered by Raj H. Maths tutor

6803 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2-6x+8=0


Rearrange to make x the subject of the equation: 4(3x+y) = 12-2y


There are 10 boys and 20 girls in a class. The class has a test. The mean mark for all the class is 60. The mean mark for the girls is 54. Work out the mean mark for the boys.


Expand and simplify (x − 4)(2x + 3y)^2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy