solve the simultaneous equations 3x+7y=18 and 7x+9y=8

3x+7y=18 (eqn 1)  -multiply by 7->   21x+49y=126 (eqn 1*)

7x+9y=8  (eqn 2)  -multiply by 3->    21x+27y=24 (eqn 2*)

(eqn 1*)-(eqn 2*)  --> 22y=102 therefor y=51/11

sub in this y value back into (eqn1) -->  3x+7(51/11)=18 --> 3x+357/11=18 --> 3x=-159/11

therefore x=-53/11

RS
Answered by Radhika S. Maths tutor

3892 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorize the following expression and solve for x: X^2 +7X +10=0


y is directly proportional to (d+2)^2, when d=5, y=147. d^2 is inversely proportional to x^2, when d=2, x=3. Find an equation for y in terms of x


How do I solve a simultaneous equation like this: 2x-5y=3, 3x+2y=14 ?


There are 720 boys and 700 girls in a school. The probability that a boy chosen at random studies French is 2/3 The probability that a girl chosen at random studies French is 3/5 . Work out the number of students in the school who study French.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning