Differentiate 4x^2 + 2ln3x + e^x

To differentiate x² you bring the power of x down, then reduce the power of x by 1, so d/dx(x²) = 2x¹

ln3x differentiates to (d/dx(3x))/3x = 3/3x = 1/x

e^x differentiates to (d/dx(x))e^x = 1e^x

Therefore, d/dx(4x² + 2ln3x + e^x) = 4(2x) +2(1/x) + e^x = 8x + 2/x + e^x