Solve 3x^2 + 13x + 14 = 0
Firstly, you need factorise.a = 3 b = 13 c = 14Find 2 numbers which add to make b(13) and multiply to make ac(42). These numbers are 6 and 7You can now split up the x coefficient to: 3x^2 + 6x + 7x + 14. You can now factorise each "half" to get to: 3x(x+2) + 7(x+2)Factor out "x+2" to get (3x+7)(x+2) = 0So the solutions are x = -7/3 or x = -2
CW
Related Maths GCSE answers
All answers ▸Solve the following simultaneous equations: 1) 2x + 7y = 12 2) 4x = 14 - 4y
Prove that the difference of the square of two consecutive odd numbers is always a multiple of 8. [OCR GCSE June 2017 Paper 5]
How do I find the missing length using trigonometry?
Solve x2 +2x – 4 = 0, leaving your answer in simplest surd form (4 marks, non calculator question)