2x+y=18, x-y=6; Solve the simultaneous equations

  1. 2x+y =182) x-y =6(x-y=6) multiply by +22x-2y = 121) 2x+y = 182) 2x-2y=12 -subtract equation 2 from equation 10x-y=6 -Therefore -y=6 so y= -6Put value for y into either of the equation in order to find value for xSo: 2x + (-6) = 18 2x - 6 = 18 2x = 24 x = 24/2 x = 12Therefore x=12, y=-6
SW
Answered by Saskia W. Maths tutor

5455 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Finding out the length of one side of a triangle


a) You area told that y is proportional to x2 and that when y = 75, x = 5. Find a formula for y in terms of x. y = x b) Find the value of y when x = 3. c) Find the value of x when y = 1200.


Draw a graph and clearly label any x and y intercepts for the equation y=x^2+6x+9


I’ve been taught two methods for solving pairs of simultaneous equations. When should I use which?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning