If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle)(x-4)(x-5)=12x2-9x+20=12x2-9x+8=0(x-8)(x-1)=0x=8 or x=1 <---- x can't be 1 as we would get negative length and widthx=8

SM
Answered by Simon M. Maths tutor

3895 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 5x + y = 21, x - 3y = 9


Solve the following simultaneous equations for x and y. 2x+5y=9 and 4x-3y=7


Complete the square on this equation: 2x^2 + 20x + 15 = 0.


Factorise x^2 -7x+10, and hence solve x^2-7x+10=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning