If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle)(x-4)(x-5)=12x2-9x+20=12x2-9x+8=0(x-8)(x-1)=0x=8 or x=1 <---- x can't be 1 as we would get negative length and widthx=8

SM
Answered by Simon M. Maths tutor

3675 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Line segment AB is drawn between point A(-3, 3) and point B(-1, -1). Work out the gradient of the line segment AB, then find the equation of the graph.


FIRSTLY: John has a slice of pizza in the exact shape of an isosceles triangle. 2 sides measure Y + 5 and 1 side measures Y – 2. Write an expression for the total perimeter. SECONDLY: Multiply out the following brackets: (3Y + 8)(3Y + 2)


solve for x: (x-2)(x+3)=2(2x+11)


In trigonometry , how do you find the angles of a right angle triangle?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning