Find the derivative of x^3 - (y^2)x =3
Differentiating with respect to x gives:3x^2 -y^2- x 2y(dy/dx) = 03x^2 -y^2 = x2y(dy/dx)dy/dx = (3x^2 - y^2)/2xy
NH
Differentiating with respect to x gives:3x^2 -y^2- x 2y(dy/dx) = 03x^2 -y^2 = x2y(dy/dx)dy/dx = (3x^2 - y^2)/2xy
