How do you take the derivative of a^x ?

There are two ways you can take the derivative of a^x.

1) 

Let y = a^x    now we're trying to find dy/dx

2)

ln(y) = xln(a)    take logs of both sides and use log rules

3)

(dy/dx)*(1/y) = ln(a)   take the derivative of both sides using the chain rule                                           on the left hand side.

4)

dy/dx = ln(a)*y              multiply both sides by y

5)

dy/dx =  ln(a) *a^x        realise y= a^x and replace it

Now we're done!

Alternatively we could realise that any exponent can be written as e to the power of something with a log in it.

So

1)

y = a^x = (e^ln(a))^x    just rewritting 'a'

2)

y = e^xln(a)                multiplying exponent rule

3)

dy/dx = ln(a)*e^xln(a)   take the derivative of both sides using the chain                                                   rule for the right hand side

4)

dy/dx  = ln(a)*a^x                         substitute back to get desired result

Answered by Expired account G. Maths tutor

3558 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you differentiate (3x+cos(x))(2+4sin(3x))?


find dy/dx for the equation y = 6x ^(1/2)+x+3


How do I expand a bracket to a negative power if it doesn't start with a 1.


Solve the inequality |x - 2sqrt(2)| > |x - 4sqrt(2)|.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy