Find the coordinates of the stationary points for the curve y = x^4 - 2*x^2 + 5.

First solve to find dy/dx.dy/dx = 4x^3 - 4xThe stationary points occur when dy/dx = 0. Solve the equation to find the values of x for when dy/dx = 0.4x(x^2 - 1) = 0 x = 0, x = 1, x = -1Finally sub in the values of x into the equation for y to find the corresponding y values.y = 5, y = 8, y = 8

MW
Answered by Matthew W. Maths tutor

5930 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that y = 16x + 1/x , find the two values of x for which dy/dx = 0


f(x) = 2x3 – 5x2 + ax + 18 where a is a constant. Given that (x – 3) is a factor of f(x), (a) show that a = – 9 (2) (b) factorise f(x) completely. (4) Given that g(y) = 2(33y ) – 5(32y ) – 9(3y ) + 18 (c) find the values of y that satisfy g(y) = 0, givi


How do I integrate by parts?


Calculate the volume obtained when rotating the curve y=x^2 360 degrees around the x axis for 0<x<2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning