Find ∫ (2x^5 - 1/(4x^3)-5) dx. giving each term in its simplest form.

with integration you need to increase the power and divide through by the new power for each term in the equation.2x⁵ goes to 2x⁶/6 = x⁶/3-1/(4x³) is equal to -x^-3/4 which then goes to -x^-2/4/-2 = x^-2/8 = 1/8x²-5 goes to -5xwith integration a constant is also added to the end. this is due to the constant disappeareing during differentiation which is the reverse of integration.so the final solution is :x⁶/3 + 1/8x² - 5x + c