Factorise (x^2-100) and then solve for x.

When looking at factorising quadratic equations, the first approach should be to identify what is in front of the x term and the value of the c term, with the equation being in the form of y=A(x^2)+Bx+c.So to factorise we first want to identify what B and C are.We then want to identify two numbers which add to the B value and multiply to the C value. These numbers are then placed in a bracket of (x+?)(x+?) to factorise the equation.However in certain tricky examples such as the one above it is not always obvious what certain terms are.In this example we have the A term as 1 as nothing is before the x^2 and the C term as -100, however we do not have a B term. In this situation we can assume that the B term is 0, as adding 0x would not change the value of the equation and still allow us to solve using our usual method.So now assuming our equation is x^2+0x-100 we can apply the method of identifying what adds up to 0 and multiplies to -100.In this example it would be -10 and 10. These are then put in front of the x value in our brackets to get (x+10)(x-10).At this point we can quickly check if we have factorised correctly by expanding our brackets.A point to note however is that the question has not been completed as it asks us also to solve for x.At this point to solve for x, we make each bracket separately=0 and then solve for x to give us our two potential x values.In this example it would be x-10=0 and x+10=0 which would result in x=-10 and x=10.