Solve the simultaneous equations: 4x+5y=13 and 3x-2y=27


Equation 1 is 4x+5y=13 - multiply it by 3, Equation 2 is 3x-2y=27 - multiply it by 4, New equation 1 is 12x+15y=39, New equation 2 is 12x-8y=108, Subtract new equation 2 from new equation 1 - 23y=-69 therefore y=-3, Substitute y=-3 into equation 1 - 4x+(5x-3)=13, 4x-15=13, 4x=28, x=7. Final answer: x=7, y=-3

TD
Answered by Thea D. Maths tutor

4772 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

expand and simplify (x+7)(2x+4)


Solve these simultaneous equations. 5x + 2y = 20 and x + 4y = 13.


What is the distance between the points with co-ordinates (3,2) and (7,9)?


Solve the following ((3x + 1)/2x ) = 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning