Expand the brackets: (3a+3)(a+4)

To expand this, we must multiply each term in both brackets separately and then add all of these terms together. First, multiply the first term in each of the brackets: 3a x a = 3a^2. Next multiply the first term in the first bracket by the second term in the second brackets: 3a x 4 = 12a. Next multiply the second term in the first brackets by the first term in the second: a x 4 = 4a. Lastly, multiply the second term in each of the brackets: 3 x 4 = 12. Now add these all up to get: 3a^2 + 12a + 4a + 12 = 3a^2 + 16a + 12

LB
Answered by Luke B. Maths tutor

4597 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations 'x-2y=3' and 'x^2+2y^2=27'


Let f ( x ) = 15 /x and g ( x ) = 2 x − 5 Find fg(4), gf(-30) and give the expression for gf(x)


Solve 3x - 5 < 16


find the coordinates of the single stationary point of the curve with equation y=8x^2 + 2/x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning