Expand the brackets: (3a+3)(a+4)

To expand this, we must multiply each term in both brackets separately and then add all of these terms together. First, multiply the first term in each of the brackets: 3a x a = 3a^2. Next multiply the first term in the first bracket by the second term in the second brackets: 3a x 4 = 12a. Next multiply the second term in the first brackets by the first term in the second: a x 4 = 4a. Lastly, multiply the second term in each of the brackets: 3 x 4 = 12. Now add these all up to get: 3a^2 + 12a + 4a + 12 = 3a^2 + 16a + 12

LB
Answered by Luke B. Maths tutor

5075 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I factorise a quadratic equation?


Solve 5x – 2 > 3x + 11


What is the Pythagoras Theorem?


A and B are points on a circle, centre O. BC is a tangent to the circle. AOC is a straight line. Angle ABO = x°. Find the size of angle ACB, in terms of x. Give your answer in its simplest form. Give reasons for each stage of your working.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning