Find the coefficient of the constant term of the expression (2x+1/(4x^3 ))^8

In order to find the coefficient we need to know which term of the binomial expansion is constant. We know the expression to find the coefficient is (8Cn)(2^n)((1/4)^(8-n)), where n is the power we are rising each variable and the variables coefficients are risen to the same power as the variables. We know both terms have a variable so we want the value n for which the variables null each other. Hence, we are looking for the term when n-3*(8-n)=0 (the -3 term comes from it being a negative power), which we can rearrange to 4n -24=0, hence n=6.Having the value of n we put it in the binomial formula and obtain the result 112.

FE
Answered by Francisco E. Maths tutor

4043 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Here is a right-angled triangle (base = 8cm and height = 9cm) and a rectangle (length = 16cm). The area of the rectangle is 6 times the area of the triangle. Work out the width of the rectangle.


Expand (x+4)(x-4)=33 to give values of x


Find the area of a sector with a radius of 5cm and an angle of 120 degrees?


Rearrange the following to make 'm' the subject. 4(m - 2) = t(5m + 3)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning