A linear sequence starts a + 2b, a +6b, a + 10b. The 2nd has a value of 8 and the 5th term has a value of 44. What are the values of a and b?

a + 6b = 8 5th term: a + 18b = 44
term 1: a + 6b = 8term 2: a + 18b = 44
term 2 - term 1: 12b = 36b = 36/12 = 3
a + 6b = 8a + 6(3) = 8a = 8-18 = -10

Answered by Leonie R. Maths tutor

2430 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Please explain the difference between compound and simple interest


How can I remember the values of sin60, sin30 sin45 e.t.c in my exams?


Find the maximum or minimum value of the function: y = 6x^2 + 4x + 2


How could you sketch a graph for y=x^2-10x+21?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy