The equation of line 1 is: 3y-5x+3=0. The equation of line 2 is : y= 5x/3+9. Check whether the 2 lines intercept.

Rearranging the first equation: 3y=5x-3Then dividing by 3 so that the equation of the line will become in the form of y=mx+c, where m is the gradient and c is the interception point with the y-axis (0,c)We get y=5x/3-1 Then by comparing the gradients of the 2 lines, it can be seen that they have the same gradient. Since the 2 lines are not the same (c1≠ c2), it can be deduced that the lines are parallel. Hence the 2 lines do not intercept.

Answered by Panagiotis G. Maths tutor

2252 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify the following equation: x^(2) +3x+4^(2)-2


Solve the simultaneous equations 5x+2y=13 and x-2y=5.


For the equation, 5(7x + 8) + 3(2x + b) ≡ ax + 13. Find the values of a and b. You may use a calculator.


Prove that (4x–5)^2 – 5x(3x – 8) is positive for all values of x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy