Describe the process of oxygen transport via haemoglobin.

Haemoglobin is a complex metal ion consisting of hexa-coordinated Fe2+ ions. With 6 coordinate bonds, haemoglobin forms an octahedral shape where 4 nitrogen ligands form a haem disc, a globin molecule forms the 5th bond, and the final bond can be interchanged between H2O and O2. An equilibrium is established by this 6th bond, following the equation: Hb(H2O)4 + 4O2 <=> Hb(O4) + 4H2O. In the lungs, oxygen concentration is higher, or increased, so equilibrium shifts right to oppose the change, meaning the H2O ligands are substituted for O2 ligands to form oxyhaemoglobin to carry oxygen through the blood. As the oxyhaemoglobin arrives at respiring tissues, oxygen concentration is low, while water concentration is higher due to respiration. Equilibrium shifts left to oppose the change, and oxygen is exchanged with water molecules. When haemoglobin reaches the lungs again, the process repeats.

Answered by Chemistry tutor

4580 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is the C-O-H bond angle in propan-2-ol and why is this? [4 marks]


Why are molecules coloured?


Which has a lower boiling point chlorine or bromine, and why?


What product is formed upon addition of dimethylamine to ethanoyl chloride? Provide a curly-arrow mechanism for the formation of this product.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning