Solve the simultaneous equation x+y=11(1), x^2+y^2=61 (2)

Make x the subject in the equation x+y=11(1). This will help us eliminate x in the second equation (2).x=11-y (3)Substitute (3) into (2)(11-y)2+y2=61Expanding the brackets and simplifying gives 2y2-22y+60=0Dividing the whole equation by 2 gives y2-11y+30=0 (4)(4) is a quadratic equationFactorise, giving (y-5)(y-6)=0There are therefore two solutions, y=5 or y=6Looking back at equation (1), when y=5, x=6when y=6, x=5
Therefore the two solutions are:x=6 y=5x=5 y=6

Answered by Maths tutor

4333 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve has an equation of y = 20x - x^2 - 2x^3, with one stationary point at P=-2. Find the other stationary point, find the d^2y/dx^2 to determine if point P is a maximum or minium.


(A) express 4^x in terms of y given that 2^x = y. (B) solve 8(4^x ) – 9(2^x ) + 1 = 0


Represent in partial fraction form the expression x/x^2-3x+2


Integrate (x^2 +2)(2x-6) with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning