Work out the value of n, the value of A & the value of B (question given below in correct subscript)

(2x3/2y-1)n = Ax6yB First of all both sides need to be written in the same format so simplify the left hand side. 2n (x3/2)n (y-1)n We are given the power of x is 6 so we can write and equation and solve to find n. x3n/2 = x6 Ignore the x as that is a constant value 3n/2 = 6 so 3n = 12 and n = 4 Now substitute n to find A and B. 24= 16 and y-1x4= y-4 This means n=4, A=16 and B=-4

ML
Answered by Megan L. Maths tutor

4330 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Why is n^0 always 1 and not 0?


Factorize 2(x^2) - 2x - 12 fully


Expand (2x + 3)(x - 1)


f(x)=2x+c, g(x) = cx+5, fg(x)= 6x+d, work out the value of d


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning