The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

We know the perimiter is split into the proportions 3:4:5 therefore by adding 3+4+5 we can work out what fraction of 72cm each side is.Thus 3/(3+4+5) = 3/12 = 1/4 is the fraction of 72 that belongs to the shortest side. This means the shorest side has lenght of 1/4 * 72 = 18cm.We can repeat this to work out the lenght of the other two sides giving the middle sized side to have lenght 4/12 * 72 = 1/3 * 72 = 24cm.And the longest side lenght 5/12 * 72 = 30cm.
We can now draw and label a sketch of the triangle.As it is a right anlged triangle we can use the formular Area = 1/2 * Base * Height. Which gives 24 * 18 * 1/2 = 12 * 18 = 10 * 18 + 2 * 18 = 216cm2

SD
Answered by Sefton d. Maths tutor

11793 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

6y+2x^2=6 x=(y+1)^0.5 solve the simultaneous equations


The diagram shows the position of two ships, A and B, and a lighthouse L. Ship A is 5km from L on a bearing of 070° from L. Ship B is 3km from L on a bearing of 210° from L. Find the distance between A and B correct to 3.s.f.


Prove the quadratic formula for ax^2 + bx + c = 0, where a is non 0 and a,b and c are reals.


Show that 0.81 reocurring = 9/11


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning