Solve the following simultaneous equations: 2x-3y=16 x+2y=-6

First, label the two equations as follows:2x-3y=16 --> [1]x+2y=-6 --> [2]To obtain the same x value for both equations, [2]2: 2x+4y=-12 --> [3]Then, to eliminate the x values from both equations, [1]-[3]: -7y=28, therefore y=-4To obtain the x value, substitute the calculated y value into either equation (could do the other to double check) as follows:Into equation [1]: 2x-3(-4)=16, therefore 2x=4, so x=2 (Check with equation [2]: x+2*(-4)=-6, therefore x=2)Alternative method would be to match the two y values to make it 6y in both equations, but given that both equations need to be altered for this, it is much more inefficient and therefore the described method is much more desirable. Answer: x=2, y=-4

MH
Answered by Masaki H. Maths tutor

3270 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise fully 27x^2 - 3


Show that 0.81 reocurring = 9/11


ABC is an isosceles triangle such that AB = AC A has coordinates (4, 37) B and C lie on the line with equation 3y = 2x + 12 Find an equation of the line of symmetry of triangle ABC. Give your answer in the form px + qy = r where p, q and are integers (5


Expand 5(2x-6)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning