Solve the simultaneous equations: 3x + 4y = 5 , 2x - 3y = 9

To solve the equations the first step to take is to eliminate one of the variables x or y so we can get the value of it and then substitute it back in to get the value of the other.
One way to do this would be to multiply the first equation by 2 in order to get 6x + 8y = 10, and the second by 3 to get 6x - 9y = 27. This allows us to subtract one equation from the other and eliminate the x value to leave us with y. So let's subtract the second equation from the first, this results in the equation 17y = -17. We can simplify this down by dividing by 17 on both sides to get y = -1.
Finally substitute y = -1 back into either equation to find x. Take the first for example: 6x + 8(-1) = 10 (substitute y = -1 in)6x - 8 = 10 (+8 both sides)6x = 18 (divide by 3 both sides)x = 3
Answer: x = 3, y = -1

YB
Answered by Yunis B. Maths tutor

4355 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The recommended price of a ladder is £75. The ladder is sold in 2 shops, one with a 30% discount the other with a discount of 2/9. How much is the discount in the two shops and which is cheaper and by how much? Non-calculator


How do I solve a quadratic equation?


2 chocolates weight 250g, there are 220 calories in 100g of chocolate. How many calories are in one chocolate?


Draw the graph of, y = x^2 – 2x – 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning