Solve the following simultaneous equations 3x+y=11 and 2x+y=8

To solve a simultaneous equation you should number your equations and re arrange one of them to make y the subject. (You could do it the other way and find the expression for x first)3x + y = 11 [1] and 2x + y = 8 [2]. Re arranging equation [1] we will get the following equation by subtracting 3x from both sides. y = 11 - 3x. Then by substituting the expression for y into equation [2] you can solve for x, giving x = 3. Then we can find the value of y by substituting the value we found for x into equation [1]3(3) + y = 11. 9 +y = 11, giving y =2

RA
Answered by Rachel A. Maths tutor

3403 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Sam works for £14 per hour. When Sam works more than 8 hours a day, he is paid overtime for each hour he works more than 8 hours at 1½ times his normal rate of pay. Sam worked for 12 hours. Work out the total amount of money Sam earned.


How do I graph linear inequalities?


Solve: 5x - 2 > 3x + 11


P (–1, 4) is a point on a circle, centre O which is at the origin. Work out the equation of the tangent to the circle at P. Give your answer in the form y = mx + c


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning