Solve the simultaneous equations 5x + y = 21 and x - 3y = 9

To begin with, I would begin by explaining that in a situation with simultaneous equations one of the variables must be eliminated to find the values for y and x.In this specific case I would make the x variables have the same coefficient and multiply the second equation by 5 giving 5x-13y=45The next step would be to subtract one equation from the other as so: 5x-13y=45 - 5x + y = 21 resulting in an answer of -16y=24This equation can rearrange to y= -1.5Using this value in either of the original equations you can solve for xBy using x-3y=9 and rearranging for x to give x=9+3y then substituting in the value for y to obtain x=4.5

LO
Answered by Lily O. Maths tutor

3228 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If a rectangle has sides (x+3) and (2x-1) and an area of 15, find x and the length of each side.


Block 1 is 24mm long. Block 2 is 32mm long. Vignesh joins some type 1 blocks together to make a straight row. He then joins some type 2 blocks together to make a straight row of the same length. (a) Write down the shortest possible length of this row.


How do you factorise a quadratic equation


The width of a rectangle is X cm.
 The length is 1·5 cm more than the width.
 The perimeter of the rectangle is 17 cm. Write down an equation satisfied by X
 and solve it to find X.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning