Differentiate y = e^(2x)cos(3x)
Using both the Chain Rule and the Product Rule for derivatives, we find the answer to be: dy/dx = e^(2x)[2cos(3x) - 3sin(3x)]
JC
Using both the Chain Rule and the Product Rule for derivatives, we find the answer to be: dy/dx = e^(2x)[2cos(3x) - 3sin(3x)]
