Given the equations: x + 3y = 1 and 2x - y = -5, solve for x and y.

Here we have 2 simultaneous equations including the variables x and y. Because we have x in one equation and 2x in another we can approach this in 2 ways. The first method is to obtain 2x in both equations so that we can equate and solve for y. If we multiply the equation x + 3y = 1 by 2 we get: 2x +6y = 2. With this we can now equate the simultaneous equations to get 2 - 6y = -5 + y, where we now only have the variable y which we can calculate as being equal to 1. With this information we can now sub y = 1 into the equation x + 3y = 1, which we solve to get x = -2. Therefore, we have solved the simultaneous equations and got x = -2 and y = 1, (we can check the results by plugging the values into the initial equations to make sure they work)

Answered by Jake F. Maths tutor

3996 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

These are the selling prices of 5 houses in 2007: £145 000, £170 000, £215 000, £90 000, £180 000. Work out the mean selling price.


Solve the simultaneous equations 5x + 3y = 24 and 3x - 4y = 26


The first four terms of an arithmetic sequence are: 3, 10, 17, 24. What is an expression, in terms of n, for the nth term?


Simplify Fully: (b^6 x b^2) / b^4


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy