how find dy/dx of parametric equations.

We start with parametric equations of x=2t+3 and y=3t^2+3t+2.
To find dy/dx, we need to work out either (dy/dt)/(dx/dt) or (dy/dt)*(dt/dx). This makes the dt's cancel each other out, allowing us to find dy/dx. First, we will differentiate our y=3t^2+3t+2. This gives us dy/dt=6t+3. To find dx/dt, differentiate x=2t+3 to give dx/dt=2.We can then do (dy/dt)/(dx/dt) to give (6t+3)/2=3t+1.5

SW
Answered by Samuel W. Maths tutor

3677 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Consider the infinite series S=Σ(from n=0 to infinite) u(down n) where u(down n)=lim (from n π to (n+1) π) ((sin t)/t) dt. Explain why the series is alternating.


Find the area R under the curve when f(x)=xcos(x) between the limits x=0 and x=2


How do you differentiate by first principles?


How do I solve this inequality: x^2>2x ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning