how find dy/dx of parametric equations.

We start with parametric equations of x=2t+3 and y=3t^2+3t+2.
To find dy/dx, we need to work out either (dy/dt)/(dx/dt) or (dy/dt)*(dt/dx). This makes the dt's cancel each other out, allowing us to find dy/dx. First, we will differentiate our y=3t^2+3t+2. This gives us dy/dt=6t+3. To find dx/dt, differentiate x=2t+3 to give dx/dt=2.We can then do (dy/dt)/(dx/dt) to give (6t+3)/2=3t+1.5

SW
Answered by Samuel W. Maths tutor

3676 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What are the set of values for x that satisfy the below equation?


Find the turning point(s) of the following function f(x) = x^2-2x+4. Determine whether the turning point is a minimum or maximum.


How do I differentiate an algebraic expression? (e.g. y=3x^4 - 8x^3 - 3) [the ^ represents x being raised to a power]


For rectangles of area 100 m^2 what is the perimeter of the rectangle with the smallest perimeter?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning