The allele y occurs with a frequency of 0.8 in a population of clams. Give the frequencies of the genotypes YY, Yy and yy.

To do this we use the Hardy-weinburg equation.p²+2pq+q²=1frequency of y = q, frequency of Y=pFirst we work out the frequency of Y(p)p+q=11-0.8=0.2p=0.2Then we plug our p and q values into the equation to find the frequency of our phenotypes.p²=0.042pq=0.32q²=0.64We can check our answers by adding them up to see if they make 10.04+0.32+0.64=1Frequency of genotype YY=0.04, Yy=0.32, yy=0.64