Solve 2x^2 + 7x + 6 = 0

2x^2 + 7x + 6 = 0
(2x + 3)(x + 2) = 0
2x +3 = 0 -> 2x = -3 -> x = -3/2
x + 2 = 0 -> x = -2
x = -3/2x = -2

Answered by Ben S. Maths tutor

1738 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you know which circle theorems to use when answering a question?


Show that (x + 4)(x + 5)(x + 6) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.


Solve the following pair of simultaneous equations: 1. 3x + 2y = 9 2. 6x + 5y = 21


What is 12x^6 / 7 divided by 4x^2 / 5 ?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy