Solve the simultaneous equations, 5x + 2y = 20 , x + 4y= 13

(Equation 1) 5x + 2y = 20 (Equation 2) x + 4y= 13
As we know the values for x and y are the same in both equations, we can use them to find out the values for both, In order to do this we need to take one equation and define it by either x or y, for example taking equation 2 and definining x in terms of y by rearranging the equation.
x + 4y = 13
x= 13 - 4y
Now we have x defined in terms of y we can put this into equation 1 and simplify to get a value for y.
5x + 2y = 20
5(13-4y) + 2y = 20
65 - 20y +2y = 20
65 - 18y = 20
-18y = -45
18y = 45
y = 2.5
Now that we have a value for y we can use that for find x. If we put our value for y into equation 2
x + 4y = 13
x + 4(2.5) = 13
x + 10 = 13
x = 3
Now we have our two values for x and y we have solved the simultaneous equations, to check they're correct we should substitute both values into either equation and see if the equation is correct.

EC
Answered by Ellen C. Maths tutor

11993 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve the #EdexcelMaths question?


A rectangle has sides of length 4x cm and (x+3)cm and has an area less than 112 cm^2, find the set of values x can take


A rectangle has an area of 20 cm^2.  Its length and width are enlarged by scale factor 3.  Find the area of the enlarged rectangle.


Factorise x^2+7x+10 to find the roots of the equatino x^2+7x+10=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning