Differentiate: y = 4x^3 - 5/x^2

To make this equation easier to differentiate it would be easier to write it using index rules as y = 4x^3 - 5x^-2 From here we can begin to differentiate: dy/dx = 3*4x^(3-1) - (-2)*5x^(-2-1) Then finally simplify the equation above to give: dy/dx = 12x^2 +10x^-3

CB
Answered by Chris B. Maths tutor

8019 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the coordinates of the point of intersection of the lines y = 5x - 2 and x + 3y = 8.


Find the first and second derivatives of: y = 6 - 3x -4x^-3, and find the x coordinates of the line's turning points


The curve y = 2x^3 - ax^2 + 8x + 2 passes through the point B where x=4. Given that B is a stationary point of the curve, find the value of the constant a.


A curve is described by the equation x^3 - 4y^2 = 12xy. a) Find the points on the curve where x = -8. b) Find the gradient at these points.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning