Differentiate: y = 4x^3 - 5/x^2

To make this equation easier to differentiate it would be easier to write it using index rules as y = 4x^3 - 5x^-2 From here we can begin to differentiate: dy/dx = 3*4x^(3-1) - (-2)*5x^(-2-1) Then finally simplify the equation above to give: dy/dx = 12x^2 +10x^-3

CB
Answered by Chris B. Maths tutor

8150 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do we know which formulas we need to learn for the exam?


Differentiate with respect to x. y(x) = e^(7x^2)


Find the values of x and y for which dy/dx = 0 in y= x^3 - 4x^2 - 3x +2


Find dy/dx of the equation (x^3)*(y)+7x = y^3 + (2x)^2 +1 at point (1,1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning