Find the area under the curve y = (4x^3) + (9x^2) - 2x + 7 between x=0 and x=2

To be able to solve this, the equation needs to be integrated. To do this, increase the power by 1 and divide by the new power.

The equation below is equal to that given in the question

y = 4(x^3) + 9(x^2) - 2(x^1) + 7(x^0).

This makes it more clear how the integration is carried out to give

x^4 + 3(x^3) - x^2 + 7x.

To find the area, the new equation needs to be solved by substituting in x=2 and x=0.

For x=2,

((2)^4) + 3((2)^3) - (2)^2 + 7(2) = 16 + 24 - 4 + 14 = 50

For x=0,

((0)^4) + 3((0)^3) - (0)^2 + 7(0) = 0.

To find the area, value for the equation with the lower value of x needs to be taken from the one with the higher. Therefore the area is given by:

area = 50 - 0 = 50

NH
Answered by Nicholas H. Maths tutor

4746 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find values of y such that: log2(11y–3)–log2(3) –2log2(y) = 1


How do we know which formulas we need to learn for the exam?


2(x^2)y + 2x + 4y – cos (PI*y) = 17. Find dy/dx using implicit differentiation.


Given df/dx=2x+3 and the graph goes through (1,1), what is the function f?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning